The nth term of the progression (frac{4}{2}), (frac{7}{3}), (frac{10}{4}), (frac{13}{5}) is …
-
A.
(frac{1 – 3n}{n + 1}) -
B.
(frac{3n + 1}{n + 1}) -
C.
(frac{3n + 1}{n – 1}) -
D.
(frac{3n – 1}{n + 1})
Correct Answer: Option B
Explanation
Using Tn = (frac{3n + 1}{n + 1}),
T1 = (frac{3(1) + 1}{(1) + 1} = frac{4}{2})
T2 = (frac{3(2) + 1}{(2) + 1} = frac{7}{3})
T3 = (frac{3(3) + 1}{(3) + 1} = frac{10}{4})
There is an explanation video available below.