The remainder when 6p3 – p2 – 47p + 30 is divided by p – 3 is
-
A.
21 -
B.
42 -
C.
63 -
D.
18
Correct Answer: Option B
Explanation
Let f(p) = 6p3 – p2 – 47p + 30
Then by the remainder theorem,
(p – 3): f(3) = remainder R,
i.e. f(3) = 6(3)3 – (3)2 – 47(3) + 30 = R
162 – 9 – 141 + 30 = R
192 – 150 = R
R = 42
There is an explanation video available below.