The remainder when 6p

^{3}– p^{2}– 47p + 30 is divided by p – 3 is-
**A.**

21 -
**B.**

42 -
**C.**

63 -
**D.**

18

##### Correct Answer: Option B

##### Explanation

Let f(p) = 6p^{3} – p^{2} – 47p + 30

Then by the remainder theorem,

(p – 3): f(3) = remainder R,

i.e. f(3) = 6(3)^{3} – (3)^{2} – 47(3) + 30 = R

162 – 9 – 141 + 30 = R

192 – 150 = R

R = 42

There is an explanation video available below.