The sum of four consecutive integers is 34. Find the least of these numbers
-
A.
7 -
B.
6 -
C.
8 -
D.
5
Correct Answer: Option A
Explanation
Let the numbers be a, a + 1, a + 2, a + 3
a + a + 1 + a + 2 + a + 3 = 34
4a = 34 – 6
4a = 28
a = (frac{28}{4})
= 7
The least of these numbers is a = 7