Home » What fraction must be subtracted from the sum of (2frac{1}{6}) and (2frac{7}{12}) to give (3frac{1}{4})?

What fraction must be subtracted from the sum of (2frac{1}{6}) and (2frac{7}{12}) to give (3frac{1}{4})?

What fraction must be subtracted from the sum of (2frac{1}{6}) and (2frac{7}{12}) to give (3frac{1}{4})?

  • A.
    (frac{1}{3})
  • B.
    (frac{1}{2})
  • C.
    (1frac{1}{6})
  • D.
    (1frac{1}{2})
Correct Answer: Option D
Explanation

(2frac{1}{6} + 2frac{7}{12})

= (frac{13}{6} + frac{31}{12})

= (frac{26 + 31}{12})

= (frac{57}{12} = frac{19}{4})

(frac{19}{4} – 3frac{1}{4})

= (frac{19}{4} – frac{13}{4})

= (frac{6}{4})

= (1frac{1}{2})

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