What is the nth term of the progression 27, 9, 3,……?

A.
27(frac{1}{3}) ^{n – 1} 
B.
3^{n + 2} 
C.
27 + 18(n – 1) 
D.
27 + 6(n – 1)
Correct Answer: Option A
Explanation
Given 27, 9, 3,……this is a G.P
r = (frac{9}{27})
= (frac{1}{3})
T = ar^{n – 1}
= 27(frac{1}{3}) ^{n – 1}