What is the nth term of the progression 27, 9, 3,……?
-
A.
27(frac{1}{3}) n – 1 -
B.
3n + 2 -
C.
27 + 18(n – 1) -
D.
27 + 6(n – 1)
Correct Answer: Option A
Explanation
Given 27, 9, 3,……this is a G.P
r = (frac{9}{27})
= (frac{1}{3})
T = arn – 1
= 27(frac{1}{3}) n – 1