What is the probability that 3 customers waiting in a bank will be served in the sequence of their arrival at the bank
-
A.
1/6 -
B.
1/3 -
C.
1/2 -
D.
2/3 -
E.
5/6
Correct Answer: Option A
Explanation
Probability that 3 customers are attended to in the sequence they arrive
= prob of attending to the 1st arrival x prob of attending to the second last x prob of attending to the last
= (frac{1}{3} times frac{1}{2} times frac{1}{1})
= (frac{1}{6})