A metal with a work function of 3.0ev is irradiated with ultraviolet light of energy 4.0 ev. The kinetic energy of the ejected electron is
-
A.
1.0eV -
B.
3.0eV -
C.
4.0eV -
D.
7.0eV
Correct Answer: Option A
Explanation
K.E = hf – Wo
= 4 – 3 = 1eV
K.E = hf – Wo
= 4 – 3 = 1eV