A pole of length L leans against a vertical wall so that it makes an angle of 60o with the horizontal ground. If the top of the pole is 8m above the ground, calculate L.
-
A.
(16sqrt{3}m) -
B.
(4sqrt{3}m) -
C.
(frac{sqrt{3}}{16}) -
D.
(frac{16sqrt{3}}{3})
Correct Answer: Option D
Explanation
(sin 60 = frac{8}{L} = 8 div frac{sqrt{3}}{2}; L = frac{8}{sin 60}=frac{16}{sqrt{3}})
When we rationalize gives (frac{16sqrt{3}}{3})