If x varies directly as y3 and x = 2 when y = 1, find x when y = 5
-
A.
2 -
B.
10 -
C.
125 -
D.
250
Correct Answer: Option D
Explanation
x (alpha) y3
x = ky3
k = (frac {x}{y^3})
when x = 2, y = 1
k = 2
Thus x = 2y3 – equation of variation
= 2(5)3
= 250