In the figure POQ is the diameter of the circle PQR. If PSR = 145o, find xo
-
A.
25o -
B.
35o -
C.
45o -
D.
125o -
E.
55o
Correct Answer: Option E
Explanation
< PRQ = (frac{1}{2}) < POQ = 90o
< PSR + < PQR = 180o
< PQR = 180o – 145o = 35o
(bigtriangleup)PQR is a right angled triangle
x = 90 – < PQR
= 90o – 35o
= 55o