In the figure, PQ is the tangent from P to the circle QRS with SR as its diameter. If QRS = (theta)oand RQP = (phi)o, which of the following relationships between (theta)o and (phi)o is correct
-
A.
(theta)o + (phi)o = 902 -
B.
(phi)o = 902 – 2(theta)o -
C.
(theta)o = (phi)o -
D.
(phi)o = 2(theta)o -
E.
(theta)o + 2(phi)o
Correct Answer: Option E
Explanation
180 – (phi)o = (theta)o + (phi)o (Sum of opposite interior angle equal to its exterior angle)
180 = 2(phi) + (theta)o