PQRS is a trapezium. QR//PS, /PQ/ = 5cm, /OR/ = 6cm, /PS/ = 10cm and angle QPS = 42o. Calculate, correct to the nearest cm2, the area of the trapezium (h = 3.35cm2 )
-
A.
27cm2 -
B.
30cm2 -
C.
36cm2 -
D.
37cm2
Correct Answer: Option A
Explanation
Area = (frac{1}{2}(a + b))h
where a = QR = 6cm
b = PA = 10cm
Area = (frac{1}{2}(6 + 10)) x 3.35cm2
= (frac{1}{2}(16)) x 3.35cm2
= 26.8cm2
= 27cm2 (approx.)