In the diagram, IG is parallel to JE, JEF = 120o and FHG = 130o,…

In the diagram, IG is parallel to JE, JEF = 120^o and FHG = 130^o, fins the angle marked t

Correct Answer: Option B

Explanation

Now, t + 60^o + 50^o = 180^o
t = 180^o – 110^o
t = 70^o