Simplify without using tables (frac{log_26}{log_28}) – (frac{log_23}{log_2frac{1}{2}})
-
A.
(frac{1}{5}) -
B.
(frac{1}{2}) -
C.
(frac{-1}{2}) -
D.
(frac{log_23}{log_27})
Correct Answer: Option A
Explanation
log26 – log23 = log2 ((frac{6}{3})) = log22
log28 – 2(frac{1}{2}) log28 – log2(frac{1}{2}) log28 – log2(frac{1}{4})
(frac{log_22}{log_232} = frac{log_22}{5log_22})
= (frac{1}{5})
N.B. log22 = 1